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JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Different Measuring Instruments

  • question_answer
    The maximum current that can be measured by a galvanometer of resistance 40 W is 10 mA. It is converted into a voltmeter that can read upto 50 V. The resistance to be connected in series with the galvanometer is ... (in ohm) [KCET 2004]

    A)         5040

    B)                        4960

    C)         2010                                 

    D)         4050

    Correct Answer: B

    Solution :

                                             \[{{i}_{g}}=\frac{50}{10\times {{10}^{-3}}}-40=4960\,\Omega \]


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