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JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Different Measuring Instruments

  • question_answer
    The current flowing in a coil of resistance 90 W is to be reduced by 90%. What value of resistance should be connected in parallel with it                                                        [MP PMT 2004]

    A)                    9 W

    B)                    90 W

    C)                    1000 W                            

    D)            10 W

    Correct Answer: D

    Solution :

                 \[{{i}_{g}}=\frac{i}{10}\] Þ Required shunt\[S=\frac{G}{(n-1)}=\frac{90}{(10-1)}=10\,\Omega \]


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