Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर
JEE Main & Advanced
Physics
Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर
Question Bank
Different Measuring Instruments
question_answer
What is the reading of voltmeter in the following figure [MP PMT 2004]
A) 3 V
B) 2 V
C) 5 V
D) 4 V
Correct Answer:
D
Solution :
Resistance between A and B \[=\frac{1000\times 500}{(1500)}=\frac{1000}{3}\] So, equivalent resistance of the circuit \[{{R}_{eq}}\]\[=500+\frac{1000}{3}=\frac{2500}{3}\] \ Current drawn from the cell \[i=\frac{10}{(2500/3)}\]\[\]\[=\frac{3}{250}A\] Reading of voltmeter i.e. potential difference across \[AB=\frac{3}{250}\times \frac{1000}{3}=4\,V\]