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JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Different Measuring Instruments

  • question_answer
    Resistance of 100 cm long potentiometer wire is 10W, it is connected to a battery (2 volt) and a resistance R in series. A source of 10 mV gives null point at 40 cm length, then external resistance R is                                                 [MP PMT 2003]

    A)         490 W                              

    B)         790 W

    C)         590 W                              

    D)         990 W

    Correct Answer: B

    Solution :

                                             \[E=\frac{e}{(R+{{R}_{h}}+r)}.\frac{R}{L}\times l\] \[\Rightarrow 10\times {{10}^{-3}}=\frac{2}{(10+R+0)}\times \frac{10}{1}\times 0.4\]Þ R = 790W


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