A) 9
B) 6
C) 3
D) 1.5
Correct Answer: C
Solution :
\[\frac{i}{{{i}_{g}}}=1+\frac{G}{S}\Rightarrow \frac{5}{0.05}=1+\frac{50}{S}\] Þ \[S=\frac{50}{99}=\frac{\rho \times l}{A}\]Þ \[l=\frac{50}{99}\times \frac{2.97\times {{10}^{-2}}\times {{10}^{-4}}}{5\times {{10}^{-7}}}=3m\].
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