JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Different Measuring Instruments

  • question_answer
    In order to pass 10% of main current through a moving coil galvanometer of 99 ohm, the resistance of the required shunt is   [MP PET 1990, 99; MP PMT 1994; RPET 2001; KCET 2003, 05]

    A)                    \[9.9\,\Omega \]

    B)                                      \[10\,\Omega \]

    C)                    \[11\,\Omega \]         

    D)            \[9\,\Omega \]

    Correct Answer: C

    Solution :

                 Shunt resistances \[S=\frac{{{i}_{g}}G}{(i-{{i}_{g}})}=\frac{10\times 99}{(100-10)}=11\Omega \]


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