JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Different Measuring Instruments

  • question_answer
    A galvanometer of resistance 36 W is changed into an ammeter by using a shunt of 4 W.  The fraction f0 of total current passing through the galvanometer is                   [BCECE 2003]

    A)         \[\frac{1}{40}\]            

    B)         \[\frac{1}{4}\]

    C)         \[\frac{1}{140}\]         

    D)         \[\frac{1}{10}\]

    Correct Answer: D

    Solution :

                                             \[\frac{{{i}_{g}}}{i}=\frac{S}{G+S}=\frac{4}{36+4}=\frac{4}{40}=\frac{1}{10}\]


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