A) 11.11 ohm
B) 9.9 ohm
C) 1.1 ohm
D) 4.4 ohm
Correct Answer: A
Solution :
\[{{i}_{g}}=i\frac{S}{G+S}\]Þ \[10\times {{10}^{-3}}=\frac{S}{100+S}\times 100\times {{10}^{-3}}\] \[90\ S=1000\Rightarrow \]\[S=\frac{1000}{90}=11.11\ \Omega \].
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