2. Questions Bank
  3. JEE Main & Advanced
  4. Mathematics
  5. Differentiation

JEE Main & Advanced Mathematics Differentiation Question Bank Derivative at a point Standard Differentiation

  • question_answer
     \[\frac{d}{dx}[{{\tan }^{-1}}(\cot x)+{{\cot }^{-1}}(\tan x)]=\]

    A)            0

    B)            1

    C)            ? 1

    D)            ? 2

    Correct Answer: D

    Solution :

               \[\frac{d}{dx}[{{\tan }^{-1}}(\cot x)+{{\cot }^{-1}}(\tan x)]\]                    =\[\frac{1(-\text{cose}{{\text{c}}^{2}}x)}{1+{{\cot }^{2}}x}-\frac{1({{\sec }^{2}}x)}{1+{{\tan }^{2}}x}=-1-1=-2\].


You need to login to perform this action.
You will be redirected in 3 sec spinner