A) ?1
B) 1
C) 0
D) None of these
Correct Answer: C
Solution :
\[\frac{d}{dx}[\cos (\sin {{x}^{2}})]=-\sin (\sin {{x}^{2}})\cos {{x}^{2}}.2x\] Putting \[x=\sqrt{\frac{\pi }{2}},\] we have \[=-2\sqrt{\frac{\pi }{2}}\sin \left( \sin \frac{\pi }{2} \right)\cos \frac{\pi }{2}=0\], \[\left[ \because \,\cos \frac{\pi }{2}=0 \right]\].
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