A) \[\frac{\pi }{180}\cos {{x}^{0}}\]
B) \[\frac{1}{90}\cos {{x}^{0}}\]
C) \[\frac{\pi }{90}\cos {{x}^{0}}\]
D) \[\frac{2}{90}\cos {{x}^{0}}\]
Correct Answer: B
Solution :
\[\frac{d}{dx}\left[ \frac{2}{\pi }\sin x{}^\circ \right]=\frac{d}{dx}\left[ \frac{2}{\pi }\sin \frac{\pi .x}{180} \right]\] \[=\frac{2}{\pi }\frac{\pi }{180}\cos \frac{x\pi }{180}=\frac{\cos x{}^\circ }{90}\] .
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