A) \[\frac{1}{y}\frac{dy}{dx}=\frac{1}{x}+\cot x\]
B) \[\frac{dy}{dx}=\frac{1}{x}+\cot x\]
C) \[\frac{1}{y}\frac{dy}{dx}=\frac{1}{x}-\cot x\]
D) None of these
Correct Answer: A
Solution :
\[y=x\sin x\]Þ\[\frac{dy}{dx}=x\cos x+\sin x\] Þ\[\frac{1}{y}\frac{dy}{dx}=\cot x+\frac{1}{x}\].
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