A) 0
B) 1
C) 2
D) 3
Correct Answer: A
Solution :
\[y={{\sec }^{-1}}\left( \frac{x+1}{x-1} \right)+{{\sin }^{-1}}\left( \frac{x-1}{x+1} \right)\] or \[y={{\cos }^{-1}}\frac{x-1}{x+1}+{{\sin }^{-1}}\left( \frac{x-1}{x+1} \right)\] \[\therefore y=\frac{\pi }{2}\Rightarrow \frac{dy}{dx}=0\] \[\left( \because {{\sin }^{-1}}x+{{\cos }^{-1}}x=\frac{\pi }{2} \right)\].
You need to login to perform this action.
You will be redirected in
3 sec
