A) \[{{(z-a)}^{2}}\]
B) \[-{{(z-a)}^{2}}\]
C) \[{{(z+a)}^{2}}\]
D) \[-{{(z+a)}^{2}}\]
Correct Answer: A
Solution :
Here \[z=a-\frac{1}{y}\]Þ \[\frac{dz}{dy}=\frac{1}{{{y}^{2}}}={{(a-z)}^{2}}\]
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