A) \[\frac{4x}{1-{{x}^{2}}}.\cos \left( \frac{1+{{x}^{2}}}{1-{{x}^{2}}} \right)\]
B) \[\frac{x}{{{(1-{{x}^{2}})}^{2}}}.\cos \left( \frac{1+{{x}^{2}}}{1-{{x}^{2}}} \right)\]
C) \[\frac{x}{(1-{{x}^{2}})}.\cos \left( \frac{1+{{x}^{2}}}{1-{{x}^{2}}} \right)\]
D) \[\frac{4x}{{{(1-{{x}^{2}})}^{2}}}.\cos \left( \frac{1+{{x}^{2}}}{1-{{x}^{2}}} \right)\]
Correct Answer: D
Solution :
\[\frac{dy}{dx}=\cos \left( \frac{1+{{x}^{2}}}{1-{{x}^{2}}} \right)\text{ }\left[ \frac{(1-{{x}^{2}})2x+(1+{{x}^{2}})2x}{{{(1-{{x}^{2}})}^{2}}} \right]\] \[=\frac{4x}{{{(1-{{x}^{2}})}^{2}}}\cos \left( \frac{1+{{x}^{2}}}{1-{{x}^{2}}} \right)\].
You need to login to perform this action.
You will be redirected in
3 sec
