JEE Main & Advanced Mathematics Differentiation Question Bank Derivative at a point Standard Differentiation

  • question_answer
    If \[y=\sin (\sqrt{\sin x+\cos x})\], then \[\frac{dy}{dx}=\] [DSSE 1987]

    A)            \[\frac{1}{2}\frac{\cos \sqrt{\sin x+\cos x}}{\sqrt{\sin x+\cos x}}\]

    B)            \[\frac{\cos \sqrt{\sin x+\cos x}}{\sqrt{\sin x+\cos x}}\]

    C)            \[\frac{1}{2}\frac{\cos \sqrt{\sin x+\cos x}}{\sqrt{\sin x+\cos x}}.(\cos x-\sin x)\]

    D)            None of these                          

    Correct Answer: C

    Solution :

               \[y=\sin (\sqrt{\sin x+\cos x})\]                    \[\frac{dy}{dx}=\frac{1}{2}\frac{\cos (\sqrt{\sin x+\cos x})}{\sqrt{\sin x+\cos x}}(\cos x-\sin x)\].


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