JEE Main & Advanced Mathematics Differentiation Question Bank Derivative at a point Standard Differentiation

  • question_answer
    If \[y=\frac{\tan x+\cot x}{\tan x-\cot x},\]then \[\frac{dy}{dx}=\]

    A)            \[2\tan 2x\sec 2x\]

    B)            \[\tan 2x\sec 2x\]

    C)            \[-\tan 2x\sec 2x\]

    D)          \[-2\tan 2x\sec 2x\]

    Correct Answer: D

    Solution :

               \[y=\frac{\tan x+\cot x}{\tan x-\cot x}=-\frac{1+{{\tan }^{2}}x}{1-{{\tan }^{2}}x}=-\sec 2x\]            \[\Rightarrow \frac{dy}{dx}=-2\sec 2x\tan 2x\].


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