A) \[{{x}^{2}}\frac{dy}{dx}+xy=0\]
B) \[{{x}^{2}}\frac{dy}{dx}+xy+2=0\]
C) \[{{x}^{2}}\frac{dy}{dx}-xy+2=0\]
D) None of these
Correct Answer: C
Solution :
\[y=x+\frac{1}{x}\]Þ \[\frac{dy}{dx}=1-\frac{1}{{{x}^{2}}}\] Therefore,\[{{x}^{2}}.\frac{dy}{dx\left( 1-\frac{1}{{}} \right)}-xy+2={{x}^{2}}\]
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