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JEE Main & Advanced Mathematics Differentiation Question Bank Derivative at a point Standard Differentiation

  • question_answer
    \[\frac{d}{dx}[(1+{{x}^{2}}){{\tan }^{-1}}x]=\]

    A)            \[x{{\tan }^{-1}}x\]

    B)            \[2{{\tan }^{-1}}x\]

    C)            \[2x{{\tan }^{-1}}x+1\]

    D)            \[x{{\tan }^{-1}}x+1\]

    Correct Answer: C

    Solution :

               \[\frac{d}{dx}[(1+{{x}^{2}}){{\tan }^{-1}}x]=1+2x{{\tan }^{-1}}x\].


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