A) \[1-\frac{1}{{{x}^{2}}}\]
B) \[1+\frac{1}{{{x}^{2}}}\]
C) \[1-\frac{1}{2x}\]
D) None of these
Correct Answer: A
Solution :
\[\frac{d}{dx}{{\left( \sqrt{x}+\frac{1}{\sqrt{x}} \right)}^{2}}=\frac{d}{dx}\left[ x+\frac{1}{x}+1 \right]=1-\frac{1}{{{x}^{2}}}\].
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