A) \[-4x\sin 2{{x}^{2}}\]
B) \[-x\sin {{x}^{2}}\]
C) \[-2x\sin 2{{x}^{2}}\]
D) \[-x\cos 2{{x}^{2}}\]
Correct Answer: C
Solution :
\[y={{(\cos {{x}^{2}})}^{2}}\]; \[\frac{dy}{dx}=2\cos {{x}^{2}}.(-\sin {{x}^{2}}).2x\] \[\frac{dy}{dx}=-4x\sin {{x}^{2}}\cos {{x}^{2}}=-2x\sin 2{{x}^{2}}\].
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