JEE Main & Advanced Mathematics Differentiation Question Bank Derivative at a point Standard Differentiation

  • question_answer
    \[{{10}^{-x\,\tan x}}\left[ \frac{d}{dx}({{10}^{x\tan x}}) \right]\] is equal to                          [AMU 2000]

    A)            \[\tan x\,+x\,\,{{\sec }^{2}}x\]

    B)            \[\ln \,10\,(\tan x+x{{\sec }^{2}}x)\]

    C)            \[\ln \,10\,\left( \tan x+\frac{x}{{{\cos }^{2}}x}+\tan x\sec x \right)\]

    D)            \[x\tan x\,\text{ln}\,\,10\]

    Correct Answer: B

    Solution :

               \[{{10}^{-x\tan x}}\frac{d}{dx}({{10}^{x\tan x}})\]            = \[{{10}^{-x\tan x}}{{.10}^{x\tan x}}.\log 10(\tan x+x{{\sec }^{2}}x)\]                    = \[\log 10(\tan x+x{{\sec }^{2}}x)\].                     


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