2. Questions Bank
  3. JEE Main & Advanced
  4. Mathematics
  5. Differentiation

JEE Main & Advanced Mathematics Differentiation Question Bank Derivative at a point Standard Differentiation

  • question_answer
    If \[y=\cos (\sin {{x}^{2}}),\]then at \[x=\sqrt{\frac{\pi }{2}},\frac{dy}{dx}\]=

    A)            ? 2

    B)            2

    C)            \[-2\sqrt{\frac{\pi }{2}}\]

    D)          0

    Correct Answer: D

    Solution :

               Since \[\frac{dy}{dx}=-\sin (\sin {{x}^{2}}).\cos {{x}^{2}}.2x\]                    Therefore, at \[x=\sqrt{\frac{\pi }{2}},\] \[\cos {{x}^{2}}=\cos \frac{\pi }{2}=0\] Þ\[\frac{dy}{dx}=0\].


You need to login to perform this action.
You will be redirected in 3 sec spinner