A) \[2x\]
B) ? 2x
C) \[2{{x}^{2}}\]
D) \[2|x|\]
Correct Answer: D
Solution :
\[f(x)=\left\{ \begin{align} & -{{x}^{2}},\ x<0 \\ & {{x}^{2}}\ \ ,\ \,\,x>0 \\ \end{align} \right.\Rightarrow f'(x)=\left\{ \begin{align} & -2x\,,\,\,x<0 \\ & 2x\,\,\,,\,\,\,\,x>0 \\ \end{align} \right.\,\,\,\] \[\therefore f'(x)=2|x|\].
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