A) \[4x\cos \,(2{{x}^{2}})\]
B) \[2\sin {{x}^{2}}\cos {{x}^{2}}\]
C) \[4x\sin ({{x}^{2}})\]
D) \[4x\sin ({{x}^{2}})\cos ({{x}^{2}})\]
Correct Answer: A
Solution :
\[\frac{d}{dx}(\sin 2{{x}^{2}})=\cos 2{{x}^{2}}.\frac{d}{dx}2{{x}^{2}}=\cos 2{{x}^{2}}.4x=4x.\cos 2{{x}^{2}}\].
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