A) \[\frac{1}{2\sqrt{\cos \sqrt{x}}}\]
B) \[\frac{\sqrt{\cos \sqrt{x}}}{2x}\]
C) \[\frac{\cos \sqrt{x}}{4\sqrt{x}\sqrt{\sin \sqrt{x}}}\]
D) \[\frac{1}{2\sqrt{\sin x}}\]
Correct Answer: C
Solution :
\[\frac{dy}{dx}=\frac{1}{2\sqrt{\sin \sqrt{x}}}\times \cos \sqrt{x}\times \frac{1}{2\sqrt{x}}\].
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