JEE Main & Advanced Mathematics Differentiation Question Bank Derivative at a point Standard Differentiation

  • question_answer
    \[\frac{d}{dx}[\cos {{(1-{{x}^{2}})}^{2}}]\]=                [AISSE 1981; AI CBSE 1979]

    A)            \[-2x(1-{{x}^{2}})\sin {{(1-{{x}^{2}})}^{2}}\]

    B)  \[-4x(1-{{x}^{2}})\sin {{(1-{{x}^{2}})}^{2}}\]

    C)            \[4x(1-{{x}^{2}})\sin {{(1-{{x}^{2}})}^{2}}\]

    D)            \[-2(1-{{x}^{2}})\sin {{(1-{{x}^{2}})}^{2}}\]

    Correct Answer: C

    Solution :

               \[\frac{d}{dx}[\cos {{(1-{{x}^{2}})}^{2}}]=-\sin {{(1-{{x}^{2}})}^{2}}\frac{d}{dx}{{(1-{{x}^{2}})}^{2}}\]                                   \[=4x(1-{{x}^{2}})\sin {{(1-{{x}^{2}})}^{2}}\].


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