A) \[\frac{2}{\sqrt{x}\sqrt{1-x}}\]
B) \[\frac{-2}{\sqrt{x}\sqrt{1-x}}\]
C) \[\frac{1}{2\sqrt{x}\sqrt{1-x}}\]
D) \[\frac{1}{\sqrt{1-x}}\]
Correct Answer: C
Solution :
\[\frac{dy}{dx}=\frac{1}{\sqrt{1-x}}.\frac{d}{dx}(\sqrt{x})=\frac{1}{2\sqrt{x}.\sqrt{1-x}}\].
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