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JEE Main & Advanced Mathematics Differentiation Question Bank Derivative at a point Standard Differentiation

  • question_answer
    \[\frac{d}{dx}({{\sin }^{-1}}x)\] is equal to                                                                    [RPET 1995]

    A)          \[\frac{1}{\sqrt{1-{{x}^{2}}}}\]

    B)   \[-\frac{1}{\sqrt{1-{{x}^{2}}}}\]

    C)            \[\frac{1}{\sqrt{1+{{x}^{2}}}}\]

    D)   \[\frac{-1}{\sqrt{1+{{x}^{2}}}}\]

    Correct Answer: A

    Solution :

               It is formula.


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