A) \[\frac{4}{49}\]
B) \[\frac{1}{7}\]
C) \[\frac{4}{7}\]
D) \[\frac{12}{49}\]
Correct Answer: C
Solution :
Second white ball can draw in two ways. (i) First is white and second is white Probability \[=\frac{4}{7}\times \frac{3}{6}=\frac{2}{7}\] (ii) First is black and second is white Probability \[=\frac{3}{7}\times \frac{4}{6}=\frac{2}{7}\] Hence required probability \[=\frac{2}{7}+\frac{2}{7}=\frac{4}{7}.\]
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