A) \[{{(5\ !)}^{2}}\]
B) \[5\ !\ \times 4\ !\]
C) \[5\ !\ \times 6\ !\]
D) \[6\times 5\ !\]
Correct Answer: C
Solution :
5 boys can be stand in a row \[5\ !\] ways Now, two girls can't stand in a row together in \[^{6}{{P}_{5}}\] ways. Total no. of required arrangement\[=5\ !\ {{\times }^{6}}{{P}_{5}}=5\ !\ \times 6\ !\].
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