JEE Main & Advanced Mathematics Permutations and Combinations Question Bank Definition of permutation, Number of permutations with or without repetition, Conditional permutations

  • question_answer
    Total number of four digit odd numbers that can be formed using 0, 1, 2, 3, 5, 7 are [AIEEE 2002]

    A) 216

    B) 375

    C) 400

    D) 720

    Correct Answer: D

    Solution :

      0, 1, 2, 3, 5, 7 : Six digits The last place can be filled in by 1, 3, 5, 7. i.e., 4 ways as the number is to be odd.  We have to fill in the remaining 3 places of the 4 digit number i.e. I, II, III place. Since repetition is allowed each place can be filled in 6 ways. Hence the 3 place can be filled in 6 × 6 × 6 = 216 ways. But in case of 0 = 216 - 36 = 180 ways. Hence by fundamental theorem, the total number will be = 180 × 4 = 720.


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