A) \[^{47}{{C}_{6}}\]
B) \[^{52}{{C}_{5}}\]
C) \[^{15}{{C}_{15}}\]
D) None of these
Correct Answer: C
Solution :
\[^{47}{{C}_{4}}+\sum\limits_{r=1}^{5}{^{52-r}{{C}_{3}}}{{=}^{51}}{{C}_{3}}{{+}^{50}}{{C}_{3}}{{+}^{49}}{{C}_{3}}{{+}^{48}}{{C}_{3}}{{+}^{47}}{{C}_{3}}{{+}^{47}}{{C}_{4}}\] \[{{=}^{51}}{{C}_{3}}{{+}^{50}}{{C}_{3}}{{+}^{49}}{{C}_{3}}{{+}^{48}}{{C}_{3}}{{+}^{48}}{{C}_{4}}\] \[{{=}^{51}}{{C}_{3}}{{+}^{50}}{{C}_{3}}{{+}^{49}}{{C}_{3}}{{+}^{49}}{{C}_{4}}\] \[{{x}_{1}}+{{x}_{2}}+.....+{{x}_{6}}\].
You need to login to perform this action.
You will be redirected in
3 sec
