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JEE Main & Advanced Chemistry The Solid State / ठोस प्रावस्था Question Bank Defects in Crystal

  • question_answer
    If \[NaCl\] is doped with \[{{10}^{-3}}mol\ %\,\,SrC{{l}_{2}},\] then the concentration of cation vacancies will be

    A)                 \[1\times {{10}^{-3}}mol%\]      

    B)                 \[2\times {{10}^{-3}}mol%\]

    C)                 \[3\times {{10}^{-3}}mol%\]      

    D)                 \[4\times {{10}^{-3}}mol%\]

    Correct Answer: A

    Solution :

                    As each \[S{{r}^{2+}}\] ion introduces one cation vacancy, therefore concentration of cation vacancies = mol % of \[SrC{{l}_{2}}\] added.


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