A) Mean, Mode, Median
B) Mean, Median, Mode
C) Mode, Median, Mean
D) Mode, Mean, Median
Correct Answer: C
Solution :
Arrangement of weights (in kg) of 9 students in ascending order is: 34, 35, 35, 35, 36, 39, 40, 40, 45 Sum of weights (in kg) of all students = 339 Mean \[=\frac{Sum\text{ }of\text{ }weights\text{ }of\text{ }all\text{ }students}{Number\text{ }of\text{ }students}\] \[=\frac{339}{9}=37.67\] Since, number of students is 9, which is odd. \[\therefore \] Median \[={{\left( \frac{9+1}{2} \right)}^{th}}\] term = 5th term = 36 Since, 35 occurs most number of times. \[\therefore \] Mode = 35. Hence, Mode < Median < Mean.You need to login to perform this action.
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