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JEE Main & Advanced Chemistry The Solid State / ठोस प्रावस्था Question Bank Crystal packing

  • question_answer
    An ionic compound has a unit cell consisting of A ions at the corners of a cube and B ions on the centres of the faces of the cube. The empirical formula for this compound would be             [CBSE PMT 2004; AIEEE 2005]

    A)                 \[AB\]  

    B)                 \[{{A}_{2}}B\]

    C)                 \[A{{B}_{3}}\]   

    D)                 \[{{A}_{3}}B\]

    Correct Answer: C

    Solution :

                    A atoms are at eight corners of the cube. Therefore, the no. of A atoms in the unit cell = \[\frac{8}{8}=1\]. B atoms are at the face centre of six faces. Therefore, its share in the unit cell = \[\frac{6}{2}=3\]. The formula is AB3.


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