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11th Class Physics Thermodynamical Processes Question Bank Critical Thinking

  • question_answer
    The enthalpy change for the reaction of 50.00 ml of ethylene with 50.00 ml of \[{{H}_{2}}\] at 1.5 atm pressure is \[\Delta H=-0.31\,kJ\]. The value of \[\Delta E\] will be  [DPMT 2004]

    A)                 ?0.3024 kJ          

    B)                 0.3024 kJ

    C)                 2.567 kJ

    D)                 ?0.0076 kJ

    Correct Answer: A

    Solution :

               \[{{C}_{2}}{{H}_{2}}(g)+{{H}_{2}}(g)\to {{C}_{2}}{{H}_{4}}(g)\]                    \[\Delta ng=1-2=-1\];  \[\Delta H=-0.31\,KJ\,mo{{l}^{-1}}\]                    \[P=1.5\,atm\], \[\Delta V=-50\,mL=-0.050L\]                    \[\Delta H=\Delta E+P\Delta V\]                                 \[-0.31=\Delta E-0.0076\];   \[\Delta E=-0.3024\,KJ\]


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