A) \[T=2\pi \sqrt{\left( \frac{Mh}{PA} \right)}\]
B) \[T=2\pi \sqrt{\left( \frac{MA}{Ph} \right)}\]
C) \[T=2\pi \sqrt{\left( \frac{M}{PAh} \right)}\]
D) \[T=2\pi \sqrt{MPhA}\]
Correct Answer: A
Solution :
Let the piston be displaced through distance x towards left, then volume decreases, pressure increases. If \[\Delta P\] is increase in pressure and \[\Delta V\] is decrease in volume, then considering the process to take place gradually (i.e. isothermal)You need to login to perform this action.
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