A) \[1\times {{10}^{2}}\]atm
B) \[2\times {{10}^{2}}at{{m}^{-1}}\]
C) \[50\,\,at{{m}^{2}}\]
D) \[5\times {{10}^{-3}}at{{m}^{2}}\]
Correct Answer: D
Solution :
\[C{{H}_{3}}OH\to CO+2{{H}_{2}}\] \[\frac{{{[{{H}_{2}}]}^{2}}[CO]}{[C{{H}_{3}}OH]}=\frac{0.1\times 0.1\times 1}{2}=\frac{0.01}{2}=\frac{10\times {{10}^{-3}}}{2}\] \[=5\times {{10}^{-3}}\].You need to login to perform this action.
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