JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Critical Thinking

  • question_answer
    The partial pressures of \[C{{H}_{3}}OH,\,CO\] and \[{{H}_{2}}\] in the equilibrium mixture for the reaction \[CO+2{{H}_{2}}\]⇌\[CH{}_{3}OH\] at 427°C are 2.0, 1.0 and 0.1 atm respectively. The value of \[{{K}_{P}}\] for the decomposition of \[C{{H}_{3}}OH\] to CO and \[{{H}_{2}}\] is [Roorkee 1999]

    A)                 \[1\times {{10}^{2}}\]atm           

    B)                 \[2\times {{10}^{2}}at{{m}^{-1}}\]

    C)                 \[50\,\,at{{m}^{2}}\]     

    D)                 \[5\times {{10}^{-3}}at{{m}^{2}}\]

    Correct Answer: D

    Solution :

               \[C{{H}_{3}}OH\to CO+2{{H}_{2}}\]                    \[\frac{{{[{{H}_{2}}]}^{2}}[CO]}{[C{{H}_{3}}OH]}=\frac{0.1\times 0.1\times 1}{2}=\frac{0.01}{2}=\frac{10\times {{10}^{-3}}}{2}\]                                 \[=5\times {{10}^{-3}}\].


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