A) \[{{\left[ \frac{2(hc+\lambda \varphi )}{m\lambda } \right]}^{1/2}}\]
B) \[\frac{2(hc-\lambda \varphi )}{m}\]
C) \[{{\left[ \frac{2(hc-\lambda \varphi )}{m\lambda } \right]}^{1/2}}\]
D) \[{{\left[ \frac{2(h\lambda -\varphi )}{m} \right]}^{1/2}}\] Where h = Planck's constant, m = mass of electron and c = speed of light.
Correct Answer: C
Solution :
According to Einstein?s photoelectric equation \[\frac{hc}{\lambda }=\varphi +\frac{1}{2}m{{v}^{2}}\Rightarrow v={{\left[ \frac{2(hc-\lambda \varphi )}{m\lambda } \right]}^{1/2}}\]
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