A) + 6 and + 2
B) + 2 and + 2
C) + 8 and + 2
D) + 6 and + 4
Correct Answer: A
Solution :
\[\overset{*\,}{\mathop{{{H}_{2}}{{S}_{2}}{{O}_{7}}}}\,\] \[2\times (+1)+2\times x+7\times (-2)=0\] \[+2+2x-14=0\] \[2x=14-2=12\] \[x=\frac{12}{2}=+6\,\,\text{for}\,\,S\] \[{{K}_{4}}\overset{*\,\,}{\mathop{Fe}}\,{{(CN)}_{6}}\] \[4\times (+1)\,x+6\times (-1)=0\] \[4+x-6=0\] \[x=6-4=+2\,\,\text{for}\,\,Fe\].
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