A) \[{{i}_{1}}\ne {{i}_{2}}\] and \[{{n}_{1}}={{n}_{2}}\]
B) \[{{i}_{1}}={{i}_{2}}\]and \[{{n}_{1}}\ne {{n}_{2}}\]
C) \[{{i}_{1}}={{i}_{2}}\] and \[{{n}_{1}}={{n}_{2}}\]
D) \[{{i}_{1}}{{n}_{1}}={{i}_{2}}{{n}_{2}}\]
Correct Answer: C
Solution :
\[{{B}_{net}}={{B}_{1}}-{{B}_{2}}\Rightarrow {{B}_{1}}-{{B}_{2}}=0\Rightarrow {{B}_{1}}={{B}_{2}}\] \[\Rightarrow B\propto ni.\]So \[{{n}_{1}}{{i}_{1}}={{n}_{2}}{{i}_{2}}\]or \[{{n}_{1}}={{n}_{2}}\,\text{and }{{i}_{1}}={{i}_{2}}\]You need to login to perform this action.
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