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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Critical Thinking

  • question_answer
    0.1 mole of \[{{N}_{2}}{{O}_{4(g)}}\] was sealed in a tube under one atmospheric conditions at 25°C. Calculate the number of moles of \[N{{O}_{2(g)}}\] present, if the equilibrium \[{{N}_{2}}{{O}_{4(g)}}\]⇌\[2N{{O}_{2(g)}}\] \[({{K}_{p}}=0.14)\] is reached after some time [UPSEAT 2001]

    A)                 \[1.8\ \times \ {{10}^{2}}\]          

    B)   \[2.8\ \times \ {{10}^{2}}\]

    C)                 0.034    

    D)                 \[2.8\ \times \ {{10}^{-2}}\]

    Correct Answer: C

    Solution :

               \[\underset{0.1}{\mathop{{{N}_{2}}{{O}_{4}}}}\,\]⇌ \[\underset{0}{\mathop{2N{{O}_{2}}}}\,\]         (.1-a)      2a       ∵ P µ 0.1          If V and T are constant (Pµ0.1+ a)         \[\text{P}=\text{(0}\text{.1}+\alpha )/0.1\]         \[{{K}_{p}}=\frac{{{[2\alpha ]}^{2}}}{[0.1-\alpha ]}\times \left[ \frac{P}{0.1+\alpha } \right]\]  or \[{{K}_{p}}=\frac{40{{\alpha }^{2}}}{[0.1-\alpha ]}=0.14\]         \[\alpha =0.017\]                                 \[N{{O}_{2}}=0.017\times 2=0.034\]mole


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