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JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Critical Thinking

  • question_answer
    At a place the value of horizontal component of the earth's magnetic field H is \[3\times {{10}^{-5}}\,Weber/{{m}^{2}}\]. A metallic rod AB of length 2 m placed in east-west direction, having the end A towards east, falls vertically downward with a constant velocity of 50 m/s. Which end of the rod becomes positively charged and what is the value of induced potential difference between the two ends                              [MP PET 1996]

    A)            End A, \[3\times {{10}^{-3}}\,mV\]                                

    B)            End A, 3 mV

    C)            End B, \[3\times {{10}^{-3}}\,mV\]                                

    D)            End B, 3 mV

    Correct Answer: B

    Solution :

                       Induced potential difference between two ends \[=Blv={{B}_{H}}lv\]            \[=3\times {{10}^{-5}}\times 2\times 50=30\times {{10}^{-3}}volt=3\,millivolt\] By Fleming's right hand rule, end A becomes positively charged.


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