A) 10.20%
B) 8.1%
C) 8.6%
D) 7.6%
Correct Answer: C
Solution :
\[{{P}_{consumed}}={{\left( \frac{{{V}_{A}}}{{{V}_{R}}} \right)}^{2}}\times {{P}_{R}}={{\left( \frac{110}{115} \right)}^{2}}\times 500=457.46\,\,W\] So, percentage drop in power output \[=\frac{(500-457.46)}{500}\times 100=8.6%\]You need to login to perform this action.
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