JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Critical Thinking

  • question_answer
    If solubility product of \[HgS{{O}_{4}}\] is \[6.4\times {{10}^{-5}}\], then its solubility is   [BHU 2004]

    A)                 \[8\times {{10}^{-3}}mole/litre\]             

    B)                 \[6.4\times {{10}^{-5}}mole/litre\]

    C)                 \[6.4\times {{10}^{-3}}mole/litre\]          

    D)                 \[2.8\times {{10}^{-6}}mole/litre\]

    Correct Answer: A

    Solution :

               \[HgS{{O}_{4}}\ \to \ \underset{x\,\,\,\,\,}{\mathop{H{{g}^{++}}}}\,+\underset{x}{\mathop{SO_{4}^{--}}}\,\]                    \[{{K}_{sp}}={{x}^{2}}\]; \[x=\sqrt{{{K}_{sp}}}\]; \[x=\sqrt{6.4\times {{10}^{-5}}}\]                                 \[x=8\times {{10}^{-3}}\]mole/litre.


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