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JEE Main & Advanced Physics Elasticity Question Bank Critical Thinking

  • question_answer
    There are two wires of same material and same length while the diameter of second wire is 2 times the diameter of first wire, then ratio of  extension produced in the wires by applying same load will be [DCE 2000; Roorkee 2000; DCE 2003]

    A) 1 : 1    

    B)             2 : 1

    C)             1 : 2    

    D)             4 : 1

    Correct Answer: D

    Solution :

                \[l=\frac{FL}{AY}\]\ \[l\propto \frac{1}{{{r}^{2}}}\] (F, L and Y are constant)             \[\frac{{{l}_{1}}}{{{l}_{2}}}={{\left( \frac{{{r}_{2}}}{{{r}_{1}}} \right)}^{2}}={{(2)}^{2}}=4\]


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