A) \[1.05\times {{10}^{-34}}\]J-sec
B) \[3.16\times {{10}^{-34}}\]J-sec
C) \[2.11\times {{10}^{-34}}\]J-sec
D) \[4.22\times {{10}^{-34}}\]J-sec (Given Planck constant \[h=6.6\times {{10}^{-34}}J-\]sec)
Correct Answer: A
Solution :
Electron after absorbing 10.2 eV energy goes to its first excited state (n=2) from ground state (n = 1). \[\therefore \]Increase in momentum \[=\frac{h}{2\pi }\] \[=\frac{6.6\times {{10}^{-34}}}{6.28}=1.05\times {{10}^{-34}}J\text{-}s\].
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