JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Critical Thinking

  • question_answer
    A steel scale measures the length of a copper wire as \[80.0\,cm,\] when both are at \[20{}^\circ C\] (the calibration temperature for scale). What would be the scale read for the length of the wire when both are at \[40{}^\circ C\]?  (Given asteel \[=11\times {{10}^{-6}}\]per°C and acopper \[=17\times {{10}^{-6}}per\,{}^\circ C\]) [CPMT 2004]

    A)            \[80.0096\,cm\]                  

    B)            \[80.0272\,cm\]

    C)            \[1\,cm\]                               

    D)            \[25.2\,cm\]

    Correct Answer: A

    Solution :

                       With temperature rise (same 25°C for both), steel scale and copper wire both expand. Hence length of copper wire w.r.t. steel scale or apparent length of copper wire after rise in temperature \[{{L}_{app}}=L{{'}_{cu}}-\,L{{'}_{steel}}=[{{L}_{0}}(1+{{\alpha }_{Cu}}\Delta \theta )-{{L}_{0}}(1+{{\alpha }_{s}}\Delta \theta )\] Þ \[{{L}_{app}}={{L}_{0}}({{\alpha }_{Cu}}-{{\alpha }_{s}})\Delta \theta \]             \[=80(17\times {{10}^{-6}}-11\times {{10}^{-6}})\times 20\] = 80.0096 cm


You need to login to perform this action.
You will be redirected in 3 sec spinner