JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Critical Thinking

  • question_answer
    The values of \[{{K}_{sp}}\]for \[CuS,\,\,A{{g}_{2}}S\] and \[HgS\] are \[{{10}^{-31}},\,{{10}^{42}}\] and \[{{10}^{-54}}\] respectively. The correct order of their solubility in water is         [MP PMT 2003]

    A)                 \[A{{g}_{2}}S>HgS>CuS\]            

    B)                 \[HgS>CuS>A{{g}_{2}}S\]

    C)                 \[HgS>A{{g}_{2}}S>CuS\]            

    D)                 \[A{{g}_{2}}S>CuS>HgS\]

    Correct Answer: D

    Solution :

               \[A{{g}_{2}}S>CuS>HgS\].                    Solubility  of CuS \[=\sqrt{{{10}^{-31}}}=3.16\times {{10}^{-16}}\,\,mol/lit.\]                    Solubility of \[A{{g}_{2}}S\]                    \[=\sqrt[3]{\frac{{{K}_{sp}}}{4}}=\sqrt[3]{\frac{{{10}^{-42}}}{4}}=6.3\times {{10}^{-5}}mole/litre\]                                 Solubility of HgS \[=\sqrt{{{K}_{sp}}}=\sqrt{{{10}^{-54}}}\]           \[={{10}^{-27}}\,\,mol/litre.\]


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